Solve Quadratic equations x^2-x+756=0 Tiger Algebra Solver (2024)

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1Factoring x2-x+756

The first term is, x2 its coefficient is 1.
The middle term is, -x its coefficient is -1.
The last term, "the constant", is +756

Step-1 : Multiply the coefficient of the first term by the constant 1756=756

Step-2 : Find two factors of 756 whose sum equals the coefficient of the middle term, which is -1.

-756+-1=-757
-378+-2=-380
-252+-3=-255
-189+-4=-193
-126+-6=-132
-108+-7=-115

For tidiness, printing of 42 lines which failed to find two such factors, was suppressed

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Equation at the end of step 1 :

 x2 - x + 756 = 0 

Step 2 :

Parabola, Finding the Vertex:

2.1Find the Vertex ofy = x2-x+756Parabolas have a highest or a lowest point called the Vertex.Our parabola opens up and accordingly has a lowest point (AKA absolute minimum).We know this even before plotting "y" because the coefficient of the first term,1, is positive (greater than zero).Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x-intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.For any parabola,Ax2+Bx+C,the x-coordinate of the vertex is given by -B/(2A). In our case the x coordinate is 0.5000Plugging into the parabola formula 0.5000 for x we can calculate the y-coordinate:
y = 1.0 * 0.50 * 0.50 - 1.0 * 0.50 + 756.0
or y = 755.750

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = x2-x+756
Axis of Symmetry (dashed) {x}={ 0.50}
Vertex at {x,y} = { 0.50,755.75}
Function has no real roots

Solve Quadratic Equation by Completing The Square

2.2Solvingx2-x+756 = 0 by Completing The Square.Subtract 756 from both side of the equation :
x2-x = -756

Now the clever bit: Take the coefficient of x, which is 1, divide by two, giving 1/2, and finally square it giving 1/4

Add 1/4 to both sides of the equation :
On the right hand side we have:
-756+1/4or, (-756/1)+(1/4)
The common denominator of the two fractions is 4Adding (-3024/4)+(1/4) gives -3023/4
So adding to both sides we finally get:
x2-x+(1/4) = -3023/4

Adding 1/4 has completed the left hand side into a perfect square :
x2-x+(1/4)=
(x-(1/2))(x-(1/2))=
(x-(1/2))2
Things which are equal to the same thing are also equal to one another. Since
x2-x+(1/4) = -3023/4 and
x2-x+(1/4) = (x-(1/2))2
then, according to the law of transitivity,
(x-(1/2))2 = -3023/4

We'll refer to this Equation as Eq. #2.2.1

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of
(x-(1/2))2 is
(x-(1/2))2/2=
(x-(1/2))1=
x-(1/2)

Now, applying the Square Root Principle to Eq.#2.2.1 we get:
x-(1/2)= -3023/4

Add 1/2 to both sides to obtain:
x = 1/2 + √ -3023/4
In Math,iis called the imaginary unit. It satisfies i2=-1. Both i and -i are the square roots of -1

Since a square root has two values, one positive and the other negative
x2 - x + 756 = 0
has two solutions:
x = 1/2 + √ 3023/4 i
or
x = 1/2 - √ 3023/4 i

Note that 3023/4 can be written as
3023 / √4which is 3023 / 2

Solve Quadratic Equation using the Quadratic Formula

2.3Solvingx2-x+756 = 0 by the Quadratic Formula.According to the Quadratic Formula,x, the solution forAx2+Bx+C= 0 , where A, B and C are numbers, often called coefficients, is given by :

-B± √B2-4AC
x = ————————
2A
In our case,A= 1
B= -1
C=756
Accordingly,B2-4AC=
1 - 3024 =
-3023
Applying the quadratic formula :

1 ± √ -3023
x=——————
2
In the set of real numbers, negative numbers do not have square roots. A new set of numbers, called complex, was invented so that negative numbers would have a square root. These numbers are written (a+b*i)

Both i and -i are the square roots of minus 1

Accordingly,-3023=
3023•(-1)=
3023•√-1=
±√ 3023 i

3023 , rounded to 4 decimal digits, is 54.9818
So now we are looking at:
x=(1± 54.982 i )/2

Two imaginary solutions :

x =(1+√-3023)/2=(1+i 3023 )/2= 0.5000+27.4909ior: 
x =(1-√-3023)/2=(1-i 3023 )/2= 0.5000-27.4909i

Two solutions were found :

  1. x =(1-√-3023)/2=(1-i 3023 )/2= 0.5000-27.4909i
  2. x =(1+√-3023)/2=(1+i 3023 )/2= 0.5000+27.4909i
Solve Quadratic equations x^2-x+756=0 Tiger Algebra Solver (2024)

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